Question 11
FrictionWhen a box of mass 45 kg is given an initial speed of 5 m s−1, it slides along a horizontal floor a distance of 3 m before coming to rest. What is the coefficient of the kinetic friction between the box and the floor? (g = 10 m s−2)
- A.5/6
- B.5/12
- C.1/3
- D.2/3.
Show the answer and explanation
Answer: B (5/12)
Explanation
Deceleration a = u²/2s = 25/6 m s−2. Friction μmg = ma, so μ = a/g = (25/6)/10 = 5/12.