Question 32
Refraction of LightA coin is placed at the bottom of a cube of glass t cm thick. If the refractive index of the glass is μ, how high does the coin appear to be raised to an observer looking perpendicularly into the glass?
- A.1/(t − μ)
- B.t(μ − 1)/μ
- C.t(1 + 1/μ)
- D.−
- E.μt.
Show the answer and explanation
Answer: B (t(μ − 1)/μ)
Explanation
Apparent depth = t/μ, so the coin seems raised by t − t/μ = t(μ − 1)/μ.