Question 10
Current ElectricityTwo cells, each of e.m.f 1.5 V and an internal resistance 2 Ω are connected in parallel. Calculate the current flowing when the cells are connected to a 1 Ω resistor
- A.0.75 A
- B.1.5 A
- C.0.5 A
- D.1.0 A
- E.0.6 A
Show the answer and explanation
Answer: A (0.75 A)
Explanation
Identical cells in parallel give e.m.f. 1.5 V and internal resistance 2 × 2/(2 + 2) = 1 Ω. I = 1.5/(1 + 1) = 0.75 A.