Question 47
ElectrostaticsIf the force on a charge of 0.2 coulomb in an electric field is 4 N, then the electric field intensity of the field is
- A.0.8
- B.0.8 N/C
- C.20.0 N/C
- D.4.2 N/C
- E.20.0 C/N
Show the answer and explanation
Answer: C (20.0 N/C)
Explanation
E = F/q = 4/0.2 = 20 N/C.