Question 46
Equilibrium of ForcesIn the given diagram (Fig. 11), the values of the vertically suspended weight W and the angle X are
- A.2 kgf, 30.9°
- B.4 kgf, 36.9°
- C.6 kgf, 53.1°
- D.8 kgf, 73.8°
- E.12 kgf, 106.2°
Show the answer and explanation
Answer: B (4 kgf, 36.9°)
Explanation
The 5 kgf string balances the 3 kgf horizontal pull and W, so 5² = 3² + W², W = 4 kgf. The angle with the vertical has sin X = 3/5, X ≈ 36.9°.