Question 18
Electrical Energy and PowerThe resistance of a 240 V, 60 watt electric filament bulb is
- A.0.25 Ω
- B.480 Ω
- C.60 Ω
- D.240 Ω
- E.960 Ω
Show the answer and explanation
Answer: E (960 Ω)
Explanation
R = V²/P = 240²/60 = 57 600/60 = 960 Ω.
The resistance of a 240 V, 60 watt electric filament bulb is
Answer: E (960 Ω)
R = V²/P = 240²/60 = 57 600/60 = 960 Ω.