Question 14
Current ElectricityA cell of e.m.f. 2 V and internal resistance 1 Ω supplies a current of 0.5 amps to a resistance whose value is
- A.0.5 Ω
- B.1 Ω
- C.2 Ω
- D.2.5 Ω
- E.3 Ω
Show the answer and explanation
Answer: E (3 Ω)
Explanation
I = E/(R + r): 0.5 = 2/(R + 1), so R + 1 = 4 and R = 3 Ω.