Question 46
Current ElectricityA cell has an open circuit voltage V1 and a closed circuit voltage V2 when a current I is flowing through it. Therefore, the internal resistance of the cell is
- A.V2/I
- B.V1/I
- C.(V1 + V2)/I
- D.(V1 − V2)/I
- E.(V2 − V1)/I.
Show the answer and explanation
Answer: D ((V1 − V2)/I)
Explanation
The open-circuit voltage is the e.m.f., V1. With current flowing, V2 = V1 − Ir, so the 'lost volts' V1 − V2 = Ir and r = (V1 − V2)/I.