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JAMB Physics 1979 Question 47

Question 47

Equilibrium of Forces

A weight of 1000 grams hangs from a lever 20 cm to the right of the fulcrum. At the left is a 500-gram weight 20 cm from the fulcrum, and a 200-gram weight x cm away from the fulcrum. What is the value of x that will make the lever balanced?

  1. A.50 cm
  2. B.20 cm
  3. C.10 cm
  4. D.30 cm
  5. E.70 cm.
Show the answer and explanation

Answer: A (50 cm)

Explanation

Moments about the fulcrum: 500 × 20 + 200 × x = 1000 × 20, so 200x = 10 000 and x = 50 cm.