Question 25
Equilibrium of ForcesA uniform beam HK of length 10 m and weighing 200 N is supported at both ends as shown in Fig. 7. A man weighing 1000 N stands at a point P on the beam. If the reactions at H and K are respectively 800 N and 400 N, then the distance HP is

- A.4 m
- B.3⅓ m
- C.3 m
- D.6⅔ m
- E.7 m
Show the answer and explanation
Answer: C (3 m)
Explanation
Take moments about H: 1000 × HP + 200 × 5 = 400 × 10. So 1000 × HP = 3000 and HP = 3 m.