JAMB Physics 1979 Question 25

Question 25

Equilibrium of Forces

A uniform beam HK of length 10 m and weighing 200 N is supported at both ends as shown in Fig. 7. A man weighing 1000 N stands at a point P on the beam. If the reactions at H and K are respectively 800 N and 400 N, then the distance HP is

Diagram for this question
  1. A.4 m
  2. B.3⅓ m
  3. C.3 m
  4. D.6⅔ m
  5. E.7 m
Show the answer and explanation

Answer: C (3 m)

Explanation

Take moments about H: 1000 × HP + 200 × 5 = 400 × 10. So 1000 × HP = 3000 and HP = 3 m.