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JAMB Physics 1978 Question 18

Question 18

Change of State and Vapours

The latent heat of fusion of ice is 80 cal g−1. How much heat is required to change 10 g of ice at 0°C into water at the same temperature?

  1. A.80 cal
  2. B.10 cal
  3. C.8 cal
  4. D.800 cal
  5. E.400 cal.
Show the answer and explanation

Answer: D (800 cal)

Explanation

Heat = mass × latent heat = 10 g × 80 cal g−1 = 800 cal.