JAMB Mathematics 2015 past questions and answers

3 questions. Try each one, then open the answer to check yourself and read the explanation.

Question 1

Progressions

The sum of the progression 1 + x + x2 + x3 + . . . =

  1. A.1/(1 − x)
  2. B.1/(1 + x)
  3. C.1/(x − 1)
  4. D.1/x
Show the answer and explanation

Answer: A (1/(1 − x))

Explanation

This is a G.P. with first term 1 and common ratio x. Its sum to infinity is a/(1 − r) = 1/(1 − x) (for −1 < x < 1).

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Question 6

Angles and Polygons

In the diagram below PQ is parallel to RS calculate the value of x

Diagram for this question
  1. A.20°
  2. B.40°
  3. C.60°
  4. D.80°
Show the answer and explanation

Answer: B (40°)

Explanation

The angle at the crossing next to 100° is 180° − 100° = 80° (angles on a straight line). In the top triangle, ∠Q = 180° − 60° − 80° = 40°. x is alternate to ∠Q because PQ∥RS, so x = 40°.

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Question 37

Matrices and Determinants

Find the matrix T if ST = I where S = (−1 1 / 1 −2) and I is the identity matrix.
(S has rows −1, 1 and 1, −2; each option lists the rows of T)

  1. A.(−2 1 / −1 1)
  2. B.(−2 −1 / −1 −1)
  3. C.(−1 −1 / 0 −1)
  4. D.(−1 1 / 0 1)
Show the answer and explanation

Answer: B ((−2 −1 / −1 −1))

Explanation

T = S−1. det S = (−1)(−2) − (1)(1) = 1. Swap the leading diagonal and change the signs of the other two entries: T = (−2 −1 / −1 −1). Check: ST gives the identity matrix.

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