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JAMB Mathematics 2013 Question 32

Question 32

Coordinate Geometry

Find the equation of the perpendicular bisector of the line joining P(2, −3) to Q(−5, 1)

  1. A.8y + 14x + 13 = 0
  2. B.8y − 14x + 13 = 0
  3. C.8y − 14x − 13 = 0
  4. D.8y + 14x − 13 = 0
Show the answer and explanation

Answer: C (8y − 14x − 13 = 0)

Explanation

The midpoint is (−3/2, −1) and PQ has gradient −4/7, so the bisector has gradient 7/4: y + 1 = 7/4 (x + 3/2). Multiplying by 8 gives 8y − 14x − 13 = 0.