Question 20
ProgressionsThe nth term of the progression 4/2, 7/3, 10/4, 13/5, ... is
- A.(3n + 1)/(n − 1)
- B.(3n + 1)/(n + 1)
- C.(1 − 3n)/(n + 1)
- D.(3n + 1)/(n + 1)
Show the answer and explanation
Answer: D ((3n + 1)/(n + 1))
Explanation
The numerators 4, 7, 10, 13 are 3n + 1 and the denominators 2, 3, 4, 5 are n + 1, so the nth term is (3n + 1)/(n + 1).