Question 31
LociThe locus of a point equidistant from the intersection of lines 3x − 7y + 7 = 0 and 4x − 6y + 1 = 0 is a
- A.line parallel to 7x + 13y + 8 = 0
- B.circle
- C.semicircle
- D.bisector of the line 7x + 13y + 8 = 0.
Show the answer and explanation
Answer: B (circle)
Explanation
Points at a fixed distance from one point (here the intersection of the two lines) form a circle centred at that point.