Question 23
Matrices and DeterminantsIf P = (x + 3 x + 2; x + 1 x − 1), evaluate x if |P| = −10. (Matrix written row by row.)
- A.−5
- B.−2
- C.2
- D.5
Show the answer and explanation
Answer: D (5)
Explanation
|P| = (x + 3)(x − 1) − (x + 2)(x + 1) = (x2 + 2x − 3) − (x2 + 3x + 2) = −x − 5. So −x − 5 = −10 and x = 5.