Question 39
IntegrationEvaluate ∫12 (6x2 − 2x) dx.
- A.16
- B.13
- C.12
- D.11
Show the answer and explanation
Answer: D (11)
Explanation
[2x3 − x2] from 1 to 2 = (16 − 4) − (2 − 1) = 11.
Evaluate ∫12 (6x2 − 2x) dx.
Answer: D (11)
[2x3 − x2] from 1 to 2 = (16 − 4) − (2 − 1) = 11.