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JAMB Mathematics 2006 Question 2

Question 2

Permutation and Combination

A final examination requires that a student answer any 4 out of 6 questions. In how many ways can this be done?

  1. A.15
  2. B.20
  3. C.30
  4. D.45
Show the answer and explanation

Answer: A (15)

Explanation

6C4 = 6!/(4! 2!) = 15.