JAMB Mathematics 2001 Question 7

Question 7

Indices

Simplify (∛(64a3))−1

  1. A.8a
  2. B.4a
  3. C.1/(4a)
  4. D.1/(8a)
Show the answer and explanation

Answer: C (1/(4a))

Explanation

The cube root of 64a3 is 4a. Raising to the power −1 gives 1/(4a).