Question 31
BearingsThe bearings of P and Q from a common point N are 020° and 300° respectively. If P and Q are also equidistant from N, find the bearing of P from Q.
- A.320°
- B.280°
- C.070°
- D.040°
Show the answer and explanation
Answer: C (070°)
Explanation
∠PNQ = 80° and NP = NQ, so the base angles are 50°. The bearing of N from Q is 120°; turning 50° towards P gives 120° − 50° = 070°.