Question 37
IntegrationA bowl is designed by revolving completely the area enclosed by y = x2 − 1, y = 0, y = 3 and x ≥ 0 around the y-axis. What is the volume of this bowl?
- A.7π cubic units
- B.15π/2 cubic units
- C.8π cubic units
- D.17π/2 cubic units
Show the answer and explanation
Answer: B (15π/2 cubic units)
Explanation
Around the y-axis, V = π∫x2 dy with x2 = y + 1. From y = 0 to 3 this is π[y2/2 + y] = π(4.5 + 3) = 15π/2.