Question 29
BearingsFrom a point P, the bearings of two points Q and R are N67°W and N23°E respectively. If the bearing of R from Q is N68°E and PQ = 150m, calculate PR.
- A.120m
- B.140m
- C.150m
- D.160m
Show the answer and explanation
Answer: C (150m)
Explanation
∠QPR = 67° + 23° = 90°. At Q the direction to P is S67°E and to R is N68°E, so ∠PQR = 180° − 67° − 68° = 45°. The right-angled triangle is isosceles, so PR = PQ = 150 m.