JAMB Mathematics 1997 Question 1

Question 1

Number Bases

If (1P03)4 = 11510, find P.

  1. A.0
  2. B.1
  3. C.2
  4. D.3
Show the answer and explanation

Answer: D (3)

Explanation

In base 4, 1P03 = 1×64 + P×16 + 0×4 + 3 = 67 + 16P. Setting 67 + 16P = 115 gives 16P = 48, so P = 3.