Question 45
Measures of DispersionClass: 1-3, 4-6, 7-9
Frequency: 5, 8, 5
Find the standard deviation of the data using the table above.
- A.5
- B.√6
- C.5/3
- D.√5
Show the answer and explanation
Answer: D (√5)
Explanation
Use the class mid-points 2, 5, 8. The mean is 5. Σf(x − 5)² = 5(9) + 8(0) + 5(9) = 90, and 90/18 = 5 is the variance, so the standard deviation is √5.