JAMB Mathematics 1994 Question 13

Question 13

Graphs of Functions

The equation of the graph above is

Diagram for this question
  1. A.y = (x − 3)3
  2. B.y = (x + 3)3
  3. C.y = x3 − 27
  4. D.y = −x3 + 27
Show the answer and explanation

Answer: A (y = (x − 3)3)

Explanation

The graph passes through (0, −27) and (3, 0), and its flat point (where it levels off) is at (3, 0). y = (x − 3)³ has exactly this: it is y = x³ shifted 3 units right.