JAMB Mathematics 1993 Question 30

Question 30

Triangles and Quadrilaterals

In the diagram above, PQ‖ST, PQR = 34°, QRS = 73° and RS = RT. Find SR̂T.

Diagram for this question
  1. A.68°
  2. B.102°
  3. C.90°
  4. D.35°
Show the answer and explanation

Answer: B (102°)

Explanation

Draw a line through R parallel to PQ. It splits the 73° at R into 34° (alternate to PQR) and 39°, so angle RST = 39°. RS = RT makes angle RTS = 39° too, so SRT = 180° − 78° = 102°.