JAMB Mathematics 1992 past questions and answers

47 questions. Try each one, then open the answer to check yourself and read the explanation.

Question 1

Number Bases

Find n if 34n = 100112

  1. A.5
  2. B.6
  3. C.7
  4. D.8
Show the answer and explanation

Answer: A (5)

Explanation

100112 = 16 + 2 + 1 = 19. So 3n + 4 = 19, giving n = 5.

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Question 2

Ratio, Percentages and Rates

The radius of a circle is given as 5cm subject to an error of 0.1cm. What is the percentage error in the area of the circle?

  1. A.1/25
  2. B.1/4
  3. C.4
  4. D.25
Show the answer and explanation

Answer: C (4)

Explanation

The radius error is 0.1/5 = 2%. Since the area depends on r2, its error is about 2 × 2% = 4% (exactly, (5.12 − 52)/52 = 4.04%).

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Question 3

Logarithms

Evaluate logb an if b = a1/n.

  1. A.n2
  2. B.n
  3. C.1/n
  4. D.1/n
Show the answer and explanation

Answer: A (n2)

Explanation

b = a1/n means a = bn, so an = bn². Hence logb an = n2.

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Question 4

Indices

What is the value of x satisfying the equation 42x/43x = 2?

  1. A.−2
  2. B.−½
  3. C.½
  4. D.2
Show the answer and explanation

Answer: B (−½)

Explanation

42x/43x = 4−x = 2−2x. Setting 2−2x = 21 gives −2x = 1, so x = −½.

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Question 6

Surds

Simplify 5√18 − 3√72 + 4√50

  1. A.17√4
  2. B.4√17
  3. C.17√2
  4. D.12√4
Show the answer and explanation

Answer: C (17√2)

Explanation

5√18 = 15√2, 3√72 = 18√2 and 4√50 = 20√2. So the total is (15 − 18 + 20)√2 = 17√2.

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Question 7

Surds

If x = 3 − √3, find x2 + 36/x2

  1. A.9
  2. B.18
  3. C.24
  4. D.27
Show the answer and explanation

Answer: C (24)

Explanation

x2 = 12 − 6√3. Then 36/x2 = 6/(2 − √3) = 6(2 + √3) = 12 + 6√3. Adding gives 24.

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Question 8

Sets

If x = (all prime factors of 44) and y = (all prime factors of 60), the element of x∪y and x∩y respectively are

  1. A.{2, 4, 3, 5, 11} and {4}
  2. B.{4, 3, 5, 11} and {3, 4}
  3. C.{2, 5, 11} and {2}
  4. D.{2, 3, 5, 11} and {2}
Show the answer and explanation

Answer: D ({2, 3, 5, 11} and {2})

Explanation

44 = 22 × 11, so x = {2, 11}; 60 = 22 × 3 × 5, so y = {2, 3, 5}. The union is {2, 3, 5, 11} and the intersection is {2}.

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Question 9

Sets

If U = {0, 2, 3, 6, 7, 8, 9, 10} is the universal set E = {0, 4, 6, 8, 10} and F = {x : x2 = 26, x is odd}. Find (E∩F)′ where ′ means the complement of a set

  1. A.{0}
  2. B.U
  3. C.{8}
  4. D.ϕ
Show the answer and explanation

Answer: B (U)

Explanation

x2 = 64 gives x = ±8, which are not odd, so F = ϕ. Then E∩F = ϕ, and the complement of the empty set is U.

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Question 10

Algebraic Expressions

Make t the subject of formula s = ut + ½ at2

  1. A.1/a[u ± √(u2 − 2as)]
  2. B.1/a[−u ± √(u2 − 2as)]
  3. C.1/a[u ± √(u2 + 2as)]
  4. D.1/a[−u ± √(u2 + 2as)]
Show the answer and explanation

Answer: D (1/a[−u ± √(u2 + 2as)])

Explanation

Rearrange as ½at2 + ut − s = 0 and use the quadratic formula: t = [−u ± √(u2 + 2as)]/a.

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Question 11

Algebraic Expressions

Factorize 9p2 − q2 + 6qr − 9r2

  1. A.(3p − 3q + r)(3p − q − 9r)
  2. B.(6p − 3q − 3r)(3q − p − 4r)
  3. C.(3p − q + 3r)(3p + q − 3r)
  4. D.(3q − p + 3r)(3q − p + 3r)
Show the answer and explanation

Answer: C ((3p − q + 3r)(3p + q − 3r))

Explanation

Group the last three terms: 9p2 − (q2 − 6qr + 9r2) = (3p)2 − (q − 3r)2 = (3p − q + 3r)(3p + q − 3r).

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Question 12

Quadratic Equations

Solve the equation y − 11√y + 24 = 0

  1. A.8, 3
  2. B.64, 9
  3. C.6, 4
  4. D.9, −8
Show the answer and explanation

Answer: B (64, 9)

Explanation

Let u = √y: u2 − 11u + 24 = 0 gives u = 3 or 8. So y = 9 or 64.

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Question 13

Commercial Arithmetic

A man invested the sum of N280.00 partly at 5% and partly at 4%. If the total interest is N12.80 per annum, find the amount invested at 5%.

  1. A.₦14.00
  2. B.₦120.00
  3. C.₦140.00
  4. D.₦160.00
Show the answer and explanation

Answer: D (₦160.00)

Explanation

Let x be at 5%: 0.05x + 0.04(280 − x) = 12.80, so 0.01x + 11.20 = 12.80 and x = ₦160.

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Question 14

Polynomials

If x + 1 is a factor of x3 + 3x2 + kx + 4, find the value of k.

  1. A.6
  2. B.−6
  3. C.8
  4. D.−8
Show the answer and explanation

Answer: A (6)

Explanation

By the factor theorem, putting x = −1 gives zero: −1 + 3 − k + 4 = 0, so k = 6.

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Question 15

Polynomials

Resolve 3/(x2 + x − 2) into partial fractions

  1. A.1/(x − 1) − 1/(x + 2)
  2. B.1/(x + 2) + 1/(x − 1)
  3. C.1/(x + 1) − 1/(x − 2)
  4. D.1/(x − 2) + 1/(x + 1)
Show the answer and explanation

Answer: A (1/(x − 1) − 1/(x + 2))

Explanation

x2 + x − 2 = (x − 1)(x + 2). Writing 3 = a(x + 2) + b(x − 1): x = 1 gives a = 1 and x = −2 gives b = −1.

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Question 16

Inequalities

Find all values of x satisfying the inequality −11 ≤ 4 − 3x ≤ 28

  1. A.−5 ≤ x ≤ 8
  2. B.5 ≤ x ≤ 8
  3. C.−8 ≤ x ≤ 5
  4. D.−5 < x ≤ 8
Show the answer and explanation

Answer: C (−8 ≤ x ≤ 5)

Explanation

Subtract 4: −15 ≤ −3x ≤ 24. Divide by −3 and reverse the signs: 5 ≥ x ≥ −8, i.e. −8 ≤ x ≤ 5.

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Question 17

Graphs of Functions

The sketch above is the curve of y = ax2 + bx + c. Find a, b and c respectively

Diagram for this question
  1. A.1, 0, −4
  2. B.−2, 2, −4
  3. C.0, 1, −4
  4. D.2, −2, −4
Show the answer and explanation

Answer: A (1, 0, −4)

Explanation

The curve cuts the y-axis at −4, is symmetric about the y-axis and opens upwards, crossing the x-axis at about ±2. So y = x2 − 4: a = 1, b = 0, c = −4.

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Question 18

Progressions

Find the sum to the infinity of the following series 3 + 2 + 4/3 + 8/9 + 16/27 + ...

  1. A.1270
  2. B.190
  3. C.18
  4. D.9
Show the answer and explanation

Answer: D (9)

Explanation

It is a G.P. with a = 3 and r = ⅔. Sum to infinity = a/(1 − r) = 3/(⅓) = 9.

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Question 19

Progressions

What is the n-th term of the sequence 2, 6, 12, 20, .......?

  1. A.4n − 2
  2. B.2(3n−1)
  3. C.n2 + n
  4. D.n2 + 3n + 2
Show the answer and explanation

Answer: C (n2 + n)

Explanation

2 = 1 × 2, 6 = 2 × 3, 12 = 3 × 4, 20 = 4 × 5, so the nth term is n(n + 1) = n2 + n.

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Question 20

Progressions

For an arithmetical sequence, the first term is 2 and the common difference is 3. Find the sum of the first 11 terms.

  1. A.157
  2. B.187
  3. C.197
  4. D.200
Show the answer and explanation

Answer: B (187)

Explanation

S11 = 11/2 × [2(2) + 10(3)] = 11/2 × 34 = 187.

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Question 21

Binary Operations

If the binary operation * is defined by m * n = mn + m + n for any real number m and n, find the identity element e under the operation

  1. A.e = 1
  2. B.e = −1
  3. C.e = −2
  4. D.e = 0
Show the answer and explanation

Answer: D (e = 0)

Explanation

We need m * e = m: me + m + e = m, so e(m + 1) = 0 for every m. Hence e = 0.

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Question 22

Matrices and Determinants

Use the matrices below to answer questions 22 and 23.
P = [x 3 0; 2 y 3; 4 2 z] (rows: x, 3, 0 / 2, y, 3 / 4, 2, z)
Q = [x 2 4; 3 y 2; 0 3 z] (rows: x, 2, 4 / 3, y, 2 / 0, 3, z)
When PT is the transpose of P, calculate |PT| when x = 0, y = 1 and z = 2

  1. A.48
  2. B.24
  3. C.−24
  4. D.−48
Show the answer and explanation

Answer: B (24)

Explanation

A matrix and its transpose have the same determinant. With x = 0, y = 1, z = 2: |P| = 0(2 − 6) − 3(4 − 12) + 0 = 24.

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Question 23

Matrices and Determinants

Use the matrices below to answer questions 22 and 23.
P = [x 3 0; 2 y 3; 4 2 z] (rows: x, 3, 0 / 2, y, 3 / 4, 2, z)
Q = [x 2 4; 3 y 2; 0 3 z] (rows: x, 2, 4 / 3, y, 2 / 0, 3, z)
PQ is equivalent to

  1. A.PPT
  2. B.PP−1
  3. C.QP
  4. D.PP
Show the answer and explanation

Answer: A (PPT)

Explanation

Q's rows are P's columns, so Q = PT and PQ = PPT.

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Question 24

Triangles and Quadrilaterals

In the fig. above, TŜP = 105° and PR̂Q = 20°, find PQ̂R

Diagram for this question
  1. A.130°
  2. B.120°
  3. C.75°
  4. D.30°
Show the answer and explanation

Answer: A (130°)

Explanation

Angle PSR = 180° − 105° = 75°. PR = SR (marked), so angle SPR = 75° and angle PRS = 30°. UQ is parallel to SR, so angle QPR = angle PRS = 30°, and in triangle PQR, PQR = 180° − 30° − 20° = 130°.

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Question 26

Circle Theorems

In the fig. above, PQR is a semicircle while PQ and QR are chords. QS is the perpendicular from Q to the diameter PR. What is the expression for QS?

Diagram for this question
  1. A.QS = PS.SR
  2. B.QS = √(PS.SR)
  3. C.QS = √2 √(PS.SR)
  4. D.QS = (1/√2) √(PS.SR)
Show the answer and explanation

Answer: B (QS = √(PS.SR))

Explanation

Angle PQR is 90° (angle in a semicircle), so triangles PSQ and QSR are similar. This gives QS/PS = SR/QS, i.e. QS2 = PS × SR.

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Question 27

Latitude and Longitude

Determine the distance on the earth's surface between two towns P(Lat. 60°N, Long. 20°E) and Q(Lat. 60°N, Long. 25°W) (Radius of the earth = 6400km)

  1. A.800π/9 km
  2. B.800√3π/9 km
  3. C.800πkm
  4. D.800√3πkm
Show the answer and explanation

Answer: C (800πkm)

Explanation

The longitude difference is 20° + 25° = 45°. The radius of latitude 60° is 6400 cos 60° = 3200km. Distance = 45/360 × 2π × 3200 = 800πkm.

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Question 28

Angles and Polygons

If in the diagram above, FG is parallel to KM, find the value of x

Diagram for this question
  1. A.75°
  2. B.95°
  3. C.105°
  4. D.125°
Show the answer and explanation

Answer: B (95°)

Explanation

Draw a line through H parallel to FG. HG makes 20° with it and HK makes 180° − 105° = 75° with it (co-interior angles with KM). So x = 20° + 75° = 95°.

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Question 29

Bearings

X is a point due east of Y on a coast. Z is another point on the coast but 6√3km due south of Y. If the distance XZ is 12km, calculate the bearing of Z from X.

  1. A.240°
  2. B.210°
  3. C.150°
  4. D.60°
Show the answer and explanation

Answer: B (210°)

Explanation

Triangle XYZ is right-angled at Y, so sin(angle YXZ) = 6√3/12 = √3/2 and angle YXZ = 60°. From X, Y is due west (270°), and Z is 60° further round towards the south: 270° − 60° = 210°.

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Question 30

Mensuration of Plane Shapes

The above diagram is a circle with centre O. Find the area of the shaded portion.

Diagram for this question
  1. A.9πcm2
  2. B.9(π − 2)cm2
  3. C.18πcm2
  4. D.36πcm2
Show the answer and explanation

Answer: B (9(π − 2)cm2)

Explanation

The shaded segment is a quarter circle of radius 6cm minus the right triangle: 90/360 × π × 36 − ½ × 6 × 6 = 9π − 18 = 9(π − 2)cm2.

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Question 31

Loci

The locus of a point which is equidistant from two given fixed points is the

  1. A.perpendicular bisector of the straight line joining them.
  2. B.parallel line to the straight line joining them
  3. C.transverse to the straight line joining them
  4. D.angle bisector of 90° which the straight line joining them makes with the horizontal.
Show the answer and explanation

Answer: A (perpendicular bisector of the straight line joining them.)

Explanation

Every point the same distance from two fixed points lies on the perpendicular bisector of the line joining them.

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Question 32

Coordinate Geometry

What is the perpendicular distance of a point (2,3) from the line 2x − 4y + 3 = 0?

  1. A.√5/2
  2. B.√5/−20
  3. C.5/√13
  4. D.0
Show the answer and explanation

Answer: A (√5/2)

Explanation

Distance = |2(2) − 4(3) + 3|/√(22 + 42) = 5/√20 = 5/(2√5) = √5/2.

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Question 33

Coordinate Geometry

Find the equation of the line through (5, 7) parallel to the line 7x + 5y = 12

  1. A.5x + 7y = 120
  2. B.7x + 5y = 70
  3. C.x + y = 7
  4. D.15x + 17y = 90.
Show the answer and explanation

Answer: B (7x + 5y = 70)

Explanation

A parallel line has the form 7x + 5y = k. Through (5, 7): k = 35 + 35 = 70.

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Question 34

Trigonometry

Given that θ is an acute angle and sin θ = m/n, find cot θ

  1. A.√((n2 − m2)/m)
  2. B.√((n + m)(n − m))/m
  3. C.m/√(n2 − m2)
  4. D.√(n/(n2 − m2))
Show the answer and explanation

Answer: B (√((n + m)(n − m))/m)

Explanation

In a right triangle with opposite side m and hypotenuse n, the adjacent side is √(n2 − m2). So cot θ = √(n2 − m2)/m = √((n + m)(n − m))/m.

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Question 35

Trigonometry

In the fig. above, if XZ is 10cm, calculate RY in cm

Diagram for this question
  1. A.10
  2. B.10(1 − 1/√3)
  3. C.10(1 − √3)
  4. D.10(1 − 1/√2)
Show the answer and explanation

Answer: B (10(1 − 1/√3))

Explanation

Angle YXZ = 30° + 15° = 45°, so YZ = 10 tan 45° = 10. RZ = 10 tan 30° = 10/√3. RY = 10 − 10/√3 = 10(1 − 1/√3).

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Question 36

Differentiation

Evaluate limx→2 (x − 2)(x2 + 3x − 2)/(x2 − 4)

  1. A.0
  2. B.2
  3. C.3
  4. D.4
Show the answer and explanation

Answer: B (2)

Explanation

Cancel (x − 2) using x2 − 4 = (x − 2)(x + 2). The limit is (4 + 6 − 2)/(2 + 2) = 8/4 = 2.

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Question 37

Differentiation

If y = x sin x, find d2y/dx2

  1. A.2cos x − x sin x
  2. B.sin x + x cos x
  3. C.sin x − x cos x
  4. D.x sin x − 2 cos x
Show the answer and explanation

Answer: A (2cos x − x sin x)

Explanation

By the product rule dy/dx = sin x + x cos x. Differentiating again: cos x + cos x − x sin x = 2cos x − x sin x.

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Question 39

Differentiation

Obtain a maximum value of the function f(x) = x3 − 12x + 11

  1. A.−5
  2. B.−2
  3. C.2
  4. D.27
Show the answer and explanation

Answer: D (27)

Explanation

f′(x) = 3x2 − 12 = 0 gives x = ±2. f″(−2) = −12 < 0, so the maximum is at x = −2: f(−2) = −8 + 24 + 11 = 27.

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Question 40

Integration

A student blows a balloon and its volume increases at a rate of π(20 − t2)cm3 s−1 after t seconds. If the initial volume is 0 cm3, find the volume of the balloon after 2 seconds.

  1. A.37.00π
  2. B.37.33π
  3. C.40.00π
  4. D.42.67π
Show the answer and explanation

Answer: B (37.33π)

Explanation

V = π(20t − t3/3), starting from 0. At t = 2: π(40 − 8/3) = 37.33π.

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Question 41

Integration

Evaluate the integral ∫π/12π/4 2 cos 2x dx

  1. A.−½
  2. B.−1
  3. C.½
  4. D.1
Show the answer and explanation

Answer: C (½)

Explanation

The integral of 2 cos 2x is sin 2x. So the value is sin(π/2) − sin(π/6) = 1 − ½ = ½.

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Question 42

Data Presentation

A storekeeper checked his stock of five commodities and arrived at the following statistics:
Commodity: F, G, H, K, M
Quantity: 215, 113, 108, 216, 68
What angle will commodity H represent on a pie chart?

  1. A.216°
  2. B.108°
  3. C.68°
  4. D.54°
Show the answer and explanation

Answer: D (54°)

Explanation

The total quantity is 720. H's angle is 108/720 × 360° = 54°.

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Question 43

Measures of Central Tendency

x: 2, 4, 6, 8
f: 4, y, 6, 5
If the mean of the above frequency distribution is 5.2, find y

  1. A.6.0
  2. B.5.2
  3. C.5.0
  4. D.4.0
Show the answer and explanation

Answer: C (5.0)

Explanation

Σfx = 8 + 4y + 36 + 40 = 84 + 4y and Σf = 15 + y. Setting (84 + 4y)/(15 + y) = 5.2 gives 84 + 4y = 78 + 5.2y, so y = 5.

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Question 44

Measures of Central Tendency

No. of children: 0, 1, 2, 3, 4, 5, 6
No. of families: 7, 11, 6, 7, 7, 5, 3
Find the mode and median respectively of the distribution above.

  1. A.2, 1
  2. B.1, 2
  3. C.1, 5
  4. D.5, 2
Show the answer and explanation

Answer: B (1, 2)

Explanation

The most common number of children is 1 (11 families), so the mode is 1. There are 46 families; the 23rd and 24th values both fall in the '2 children' group (cumulative 7, 18, 24), so the median is 2.

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Question 45

Measures of Dispersion

If the scores of 3 students in a test are 5, 6 and 7, find the standard deviation of their scores.

  1. A.2/3
  2. B.2/(3√3)
  3. C.√(2/3)
  4. D.√3/2
Show the answer and explanation

Answer: C (√(2/3))

Explanation

The mean is 6, and the squared deviations are 1, 0 and 1. Variance = 2/3, so the standard deviation is √(2/3).

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Question 46

Measures of Dispersion

Sample variance can be defined as S2 = (1/n) Σ (xi − x̄)2 and S2 = (1/(n − 1)) Σ (xi − x̄)2 where n is the number of sample observations. There is no difference practically between the above definitions when

  1. A.n ≠ 35
  2. B.n > 35
  3. C.n < 35
  4. D.n = 5
Show the answer and explanation

Answer: B (n > 35)

Explanation

Dividing by n or by n − 1 gives almost the same result when n is large, so the two definitions agree in practice for large samples (n > 35 here).

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Question 47

Probability

Two perfect dice are thrown together. Determine the probability of obtaining a total score of 8.

  1. A.1/12
  2. B.5/36
  3. C.1/6
  4. D.7/36
Show the answer and explanation

Answer: B (5/36)

Explanation

A total of 8 comes from (2,6), (3,5), (4,4), (5,3) and (6,2): 5 of the 36 outcomes.

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Question 48

Probability

The probability of an event P is 3/4 while that of another event Q is 1/6. If the probability of both P and Q is 1/12, what is the probability of either P or Q?

  1. A.1/96
  2. B.1/8
  3. C.5/6
  4. D.11/12
Show the answer and explanation

Answer: C (5/6)

Explanation

P(P or Q) = P(P) + P(Q) − P(both) = 9/12 + 2/12 − 1/12 = 10/12 = 5/6.

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Question 49

Permutation and Combination

Five people are to be arranged in a row for a photograph. How many arrangements are there if a married couple in the group insists on sitting next to each other?

  1. A.48
  2. B.24
  3. C.20
  4. D.10
Show the answer and explanation

Answer: A (48)

Explanation

Treat the couple as one block, so 4 items are arranged in a row in 4! = 24 ways. The couple can swap places within the block, giving 24 × 2 = 48.

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Question 50

Permutation and Combination

A student has five courses to take from Mathematics and Physics. There are 4 courses in Mathematics and 3 in Physics which he can choose from at will. In how many ways can he choose his courses such that he takes exactly two courses in Physics.

  1. A.11
  2. B.12
  3. C.10
  4. D.7
Show the answer and explanation

Answer: B (12)

Explanation

He chooses 2 of the 3 Physics courses (3 ways) and the other 3 courses from the 4 Mathematics courses (4 ways). 3 × 4 = 12.

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