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JAMB Mathematics 1991 Question 38

Question 38

Triangles and Quadrilaterals

In the figure above, PQ = PR = PS and SR̂T = 68°, Find QP̂S.

Diagram for this question
  1. A.136°
  2. B.124°
  3. C.112°
  4. D.68°
Show the answer and explanation

Answer: A (136°)

Explanation

Angle QRS = 180° − 68° = 112°. Triangles PQR and PRS are isosceles, so angle QPR + angle RPS = (180° − 2 × PRQ) + (180° − 2 × PRS) = 360° − 2 × 112° = 136°.