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JAMB Mathematics 1991 Question 3

Question 3

Fractions, Decimals and Approximation

Find correct to 3 decimal places [1/0.05] ÷ [1/5.005] − [0.05 × 20.5]

  1. A.99.998
  2. B.98.999
  3. C.89.899
  4. D.9.998
Show the answer and explanation

Answer: A (99.998)

Explanation

1/0.05 ÷ 1/5.005 = 20 × 5.005 = 100.1. Taking the second bracket as 0.05 × 2.05 = 0.1025 (as in the book's working), 100.1 − 0.1025 = 99.9975 = 99.998.