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JAMB Mathematics 1990 Question 2

Question 2

Algebraic Expressions

The H.C.F of a2bx + ab2x and a2b − b3 is

  1. A.b
  2. B.a + b
  3. C.b(a + b)
  4. D.abx(a2 − b2)
Show the answer and explanation

Answer: C (b(a + b))

Explanation

a2bx + ab2x = abx(a + b) and a2b − b3 = b(a − b)(a + b). The factors common to both are b and (a + b), so the H.C.F. is b(a + b).