Question 32
TrigonometryIf cos θ = a/b, find 1 + tan2θ
- A.b2/a2
- B.a2/b2
- C.(a2 + b2)/(b2 − a2)
- D.(2a2 + b2)/(a2 + b2)
Show the answer and explanation
Answer: A (b2/a2)
Explanation
1 + tan²θ = sec²θ = 1/cos²θ = b²/a².
If cos θ = a/b, find 1 + tan2θ
Answer: A (b2/a2)
1 + tan²θ = sec²θ = 1/cos²θ = b²/a².