Question 18
IndicesIf 32y − 6(3y) = 27, find y
- A.3
- B.−1
- C.2
- D.−3
- E.1.
Show the answer and explanation
Answer: C (2)
Explanation
Put u = 3ʸ: u² − 6u − 27 = 0, so (u − 9)(u + 3) = 0. 3ʸ cannot be negative, so 3ʸ = 9 and y = 2.
If 32y − 6(3y) = 27, find y
Answer: C (2)
Put u = 3ʸ: u² − 6u − 27 = 0, so (u − 9)(u + 3) = 0. 3ʸ cannot be negative, so 3ʸ = 9 and y = 2.