Question 43
TrigonometryIf sin θ = x/y and 0° < θ < 90° then find 1/tan θ
- A.x/√(y2 − x2)
- B.y/x
- C.√(y2 − x2)/x
- D.√(y2 + x2)/√(y2 + x2)
- E.√(x2 − y2)/y
Show the answer and explanation
Answer: C (√(y2 − x2)/x)
Explanation
With opposite side x and hypotenuse y, the adjacent side is √(y² − x²). 1/tan θ = adjacent/opposite = √(y² − x²)/x.