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JAMB Chemistry 2024 Question 21

Question 21

Volumetric Analysis

Calculate the volume of 0.1mH2SO4 that will be required to neutralize 45.0cm3 of a 0.2 MNaOH?

  1. A.20.0cm3
  2. B.10.0cm3
  3. C.45.0cm3
  4. D.30.0cm3
Show the answer and explanation

Answer: C (45.0cm3)

Explanation

H2SO4 + 2NaOH → Na2SO4 + 2H2O. Moles NaOH = 0.2 × 0.045 = 0.009, so acid = 0.0045 mol; volume = 0.0045/0.1 = 0.045 dm3 = 45.0 cm3.