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JAMB Chemistry 2014 Question 9

Question 9

Atomic Structure

How many protons, neutrons and electrons respectively are present in the element 6027Co?

  1. A.27, 33 and 33.
  2. B.33, 27 and 27.
  3. C.27, 33 and 27.
  4. D.60, 33 and 60.
Show the answer and explanation

Answer: C (27, 33 and 27.)

Explanation

Protons = atomic number = 27; neutrons = 60 − 27 = 33; a neutral atom has as many electrons as protons, 27.