Question 15
Solubility and Solutions16.55 g of lead(II) trioxonitrate(V) was dissolved in 100 g of distilled water at 20 °C, calculate the solubility of the solute in mol dm-3. [Pb = 207, N = 14, O = 16]
- A.0.05 g
- B.2.00 g
- C.1.00 g
- D.0.50 g
Show the answer and explanation
Answer: D (0.50 g)
Explanation
Molar mass of Pb(NO3)2 = 207 + 2(14 + 48) = 331 g, so 16.55 g = 0.05 mol in 100 g of water. In 1000 g (about 1 dm3) that is 0.50 mol dm-3.