Question 22
Redox Reactions2H2O(l) + 2F2(g) → 4HF(aq) + O2(g)
In the reaction above, the substance that is being reduced is
- A.O2(g)
- B.H2O(l)
- C.F2(g)
- D.HF(aq)
Show the answer and explanation
Answer: C (F2(g))
Explanation
Fluorine goes from 0 in F2 to −1 in HF: it gains electrons, so it is reduced.