Question 11
Solubility and SolutionsFrom the diagram above, find the amount of solute deposited when 200cm3 of the solution is cooled from 55°C to 40°C.

- A.0.10 mole
- B.0.20 mole
- C.0.01 mole
- D.0.02 mole
Show the answer and explanation
Answer: B (0.20 mole)
Explanation
From the graph the solubility falls by about 1 mole per dm3 between 55 °C and 40 °C. For 200 cm3 (0.2 dm3): 1 × 0.2 = 0.20 mole is deposited.