Question 4
Mole Concept and Stoichiometry0.0075 mole of calcium trioxocarbonate(IV) is added to 0.015 mole of a solution of hydrochloric acid. The volume of gas evolved at s.t.p. is [Molar volume of a gas at s.t.p. = 22.4 dm3]
- A.224 cm3
- B.168 cm3
- C.112 cm3
- D.100 cm3
Show the answer and explanation
Answer: B (168 cm3)
Explanation
CaCO3 + 2HCl → CaCl2 + H2O + CO2. 0.0075 mol CaCO3 uses exactly 0.015 mol HCl and gives 0.0075 mol CO2 = 0.0075 × 22 400 = 168 cm3.