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JAMB Chemistry 2009 Question 24

Question 24

Electrolysis

What current will deposit 3.25g of zinc in 2 hrs? [Zn = 65, F = 96500 mol−1]

  1. A.3.25A
  2. B.2.00A
  3. C.1.34A
  4. D.0.67A
Show the answer and explanation

Answer: C (1.34A)

Explanation

3.25/65 = 0.05 mol Zn needs 2 × 0.05 = 0.1 F = 9650 C. I = 9650/7200 s ≈ 1.34 A.