Question 22
Redox ReactionsThe oxidation state of Cr in K2Cr2O7 is
- A.+7
- B.+6
- C.+5
- D.4
Show the answer and explanation
Answer: B (+6)
Explanation
2(+1) + 2x + 7(−2) = 0, so 2x = 12 and x = +6.
The oxidation state of Cr in K2Cr2O7 is
Answer: B (+6)
2(+1) + 2x + 7(−2) = 0, so 2x = 12 and x = +6.