Question 19
Mole Concept and StoichiometryWhat volume of 1.5 M solution of KOH would contain 0.045 moles?
- A.67.50cm3
- B.30.00cm3
- C.6.75cm3
- D.3.00cm3
Show the answer and explanation
Answer: B (30.00cm3)
Explanation
Volume = moles ÷ concentration = 0.045/1.5 = 0.030 dm3 = 30 cm3.