Question 15
Solubility and SolutionsIf 10.5g of lead (II) trioxonitrate (V) is dissolved in 20cm3 of distilled water at 180C, the solubility of the solute in mol dm−3 is [Pb = 207, N = 14, O = 16]
- A.1.60
- B.5.25
- C.16.00
- D.525.00
Show the answer and explanation
Answer: A (1.60)
Explanation
Pb(NO3)2 = 331 g/mol, so 10.5 g = 0.0317 mol. In 1000 cm3: 0.0317 × 1000/20 ≈ 1.60 mol dm−3.