Question 50
Mole Concept and StoichiometryWhat weight of NaCl is needed to make 2.0 dm3 of a 1.5M solution? [Na = 23, Cl = 35.5]
- A.116 g
- B.175 g
- C.87 g
- D.58 g.
Show the answer and explanation
Answer: B (175 g)
Explanation
Moles = 1.5 × 2.0 = 3.0 mol. Mass = 3.0 × 58.5 = 175.5 g ≈ 175 g.