Question 28
Gas LawsWhat is the volume of oxygen required to burn completely 45 cm3 of methane at s.t.p.?
- A.135.0 cm3
- B.180.0 cm3
- C.45.0 cm3
- D.90.0 cm3
Show the answer and explanation
Answer: D (90.0 cm3)
Explanation
CH4 + 2O2 → CO2 + 2H2O. By Gay-Lussac's law 1 volume of methane needs 2 volumes of oxygen: 2 × 45 = 90 cm3.