Question 26
Mole Concept and StoichiometryCalculate the mass of chlorine gas which occupies a volume of 1.12 dm3 at s.t.p. [Cl=35.5, Molar volume of gas at s.t.p. = 22.4 dm3]
- A.15.50 g
- B.7.10 g
- C.3.55 g
- D.1.80 g.
Show the answer and explanation
Answer: C (3.55 g)
Explanation
Moles of Cl2 = 1.12/22.4 = 0.05 mol. Mass = 0.05 × 71 = 3.55 g.