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JAMB Chemistry 2007 Question 23

Question 23

Mole Concept and Stoichiometry

Calculate the number of moles of HCl present in 20 cm3 of a 0.75M solution of the acid.

  1. A.0.015 mole
  2. B.0.038 mole
  3. C.3.800 moles
  4. D.1.500 moles.
Show the answer and explanation

Answer: A (0.015 mole)

Explanation

Moles = concentration × volume in dm3 = 0.75 × 20/1000 = 0.015 mol.