Question 43
Energy ChangesH2(g) + Br2(g) → 2HBr(g)
The reaction above is carried out at 25°C. If ΔH is −72 kJ mol−1 and ΔS is − 106 J mol−1 K−1, the reaction will
- A.not proceed spontaneously at the given temperature
- B.proceed spontaneously at the given temperature
- C.proceed in the reverse direction at the given temperature
- D.proceed spontaneously at lower temperatures.
Show the answer and explanation
Answer: B (proceed spontaneously at the given temperature)
Explanation
ΔG = ΔH − TΔS = −72 − (298 × −0.106) = −72 + 31.6 = −40.4 kJ mol−1. A negative ΔG means it proceeds spontaneously at 25°C.