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JAMB Chemistry 2006 Question 40

Question 40

Mole Concept and Stoichiometry

2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g)
In the reaction above, the mass of carbon(IV)oxide produced on burning 78 g of ethyne is [C = 12, O = 16, H = 1]

  1. A.264 g
  2. B.39 g
  3. C.352 g
  4. D.156 g
Show the answer and explanation

Answer: A (264 g)

Explanation

78 g ÷ 26 g/mol = 3 mol of ethyne. Each mole gives 2 mol CO2, so 6 mol × 44 g = 264 g.