Question 32
Mole Concept and StoichiometryThe volume of 2.5 moles of oxygen at s.t.p. is [Molar volume of a gas at s.t.p. = 22.4 dm3]
- A.50.0 dm3
- B.84.0 dm3
- C.28.0 dm3
- D.56.0 dm3
Show the answer and explanation
Answer: D (56.0 dm3)
Explanation
Volume = moles × molar volume = 2.5 × 22.4 = 56.0 dm3.